推荐回答（2个）
哪里是众所周知的,它的强碱性,减少权力, 但是不为其醇氧化能力感兴趣.
实验观察,我们决定去探索下去,作为一个有用的醇氧化虽然它可能想象的那样 .氮原子的基本吡啶的构造深度贴图 ,可能有中发挥了作用,促进氢化物淘汰,相应的材料,中间有进一步的调查, 在一范围内的其他中等醇基质迅速披露 ,这不是一个结构所需的活性,从而,开放其广泛的基体的范围。
结果编制计划3.Among许多中学
根据氢化钠，芳基和杂醇调查行动
醇的结构概括为3被发现基板
选择，而烷基醇，丙炔醇要么没有了
反应或复杂的氧化分解mixtures.The
发生地在室温下，前往完成
通常在16-36医管局四氢呋喃溶剂中筛选，二甲基甲酰胺，
甲苯和乙醚四氢呋喃是建立optimal.Our
初步计算模型这部小说的氧化过程
还建议，协调的四氢呋喃的钠原子
可能在降低发挥了重要作用氢化
消除能源中间A.对酮的分离率
产品4一般都很高，除在substratesbearing一缺电子取代基，其中其对应的案件，
荷兰国际集团的产品，如11和15人获得大幅调低
yields.This明显的电子效应可以合理地
归因于产生高酮羰基的困难
亲电性，从氢消除pathway.The
氧化协议是极其简单的业务;制作
在5-8和13-14在5克尺度，例如，已经一应俱全
可实施不影响产量和缓解孤立
操纵，并在所有情况下的产品很容易分离
从溶液中，当需要，前水
workup，NaH和四氢呋喃均可以定量收回
过滤下氮气和反应混合物
随后蒸发的solvent.6没有这样的问题，因为
金属残渣或分解废物，是招致
氧化剂itself.The的反应似乎是敏感的空间位阻
环境的烷基- 3型组，并取代甲基
在12-14组与异丙造成损失的反应
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