解:由a+b=3,a^2+b^2=10可得ab=-1/2
a^2b-4a^2b^2+ab^2=ab(a+b)-4a^2b^2
=3ab-4a^2b^2
=ab(3-4ab)
=-5/2
a^2+b^2=10
a+b=3 (a+b)^2=9 a^2+b^2+2ab=9 10+2ab=9 ab=-1/2
a^2b-4a^2b^2+ab^2
=ab(a-4ab+b)
=ab(a+b-4ab)
=-1/2*(3+4/2)
=-5/2
2ab=3*3-10=-1
代数式=ab(a-4ab+b)=-1/2(3+2)=-5/2
(a+b)^2=a^2+2ab+b^2,
9=10+2ab,
ab=-1/2
所以a^2b-4a^2b^2+ab^2
=ab(a-4ab+b)
=(-1/2)(3+2)
=-5/2
-0.5