求简单计算方法1⼀2+2⼀3+3⼀4+4⼀5+5⼀6+6⼀7+7⼀8+8⼀9+9⼀10=?

2024-11-14 05:04:19
推荐回答(3个)
回答1:

1/2+2/3+3/4+4/5+5/6+6/7+7/8+8/9+9/10
=1-1/2+1-1/3+1-1/4+1-1/5+1-1/6+1-1/7+1-1/扰谈8+1-1/9+1-1/10
=9-(1/2+1/3+1/6)-(1/4+1/8)-(1/搜李敏5+1/世枝10)-1/7-1/9
=9-1-3/8-3/10-1/7-1/9
=8-2341/2520
=7又2520分之179

回答2:

=(1-1/2)+(1-1/3)+...(1-1/宴携雀10)
=9-(1/2+1/3+...1/10)
=9-[1/2+1/3+1/4+1/5+1/晌早6+1/7+1/8+1/9+1/10]
=9-[(1/2+1/3+1/6)+(1/4+1/5+1/10)+1/7+1/8+1/隐轮9]
=9-(1+11/20+1/8+1/7+1/9)
=9-(1+27/40+1/9+1/7)
=9-(1+283/360+1/7)
=8-2341/2520

回答3:

1/含中2+2/3+3/4+4/5+5/6+6/7+7/8+8/9+9/10
=9-(1/2+1/3+1/手羡4+1/5+1/6+1/7+1/8+1/9+1/谈薯山10)