已知液体流量、密度及管程,如何确定管道直径、液体流速

2025-03-16 15:37:53
推荐回答(2个)
回答1:

初算一下流量12t/h,就是12m³/h,12÷3600=0.003333m³/s, DN20管的面积A=πd²/4=3.1416*(0.020m)²/4=0.00031416m²。
流速V=Q/A=0.003333/0.00031416=10.61m/s.所以不可能是1m/s,因此选择直径20mm管是不行的。至于热力计算表可以去百度一下,因为你计算的是流体力学,不涉及很多热力性能,但是要用到运动粘度系数和密度,可以去百度查“动力粘度系数表”,然后算水(汽)的运动粘度系数ν,先算雷诺数Re,再算圆管层流的沿程阻力系数λ=64/Re.估计4米长管子以你1m/s的流速是没有什么阻力的。一般水在圆管里的经济流速是2米/秒。水在130°C,0.2MPa时是蒸汽。基本网上大多可以查到热力性能表的。你的液体比水重,要知道是什么液体才可以找到热力性能表,计算方法与水同。你的问题属于“流体力学”范畴。以上是以水来举例的,没有按你的液体算。
你的液体体积流量是12000/1500=8m³,8m³/h=0.002222m³/s。V=0.002222/0.00031416=7.1m/s.
也太快了。计算中要统一度量衡。本人不是这专业的,凭工作经验不一定对,仅供参考。

回答2:

这涉及化工原理范畴,现在可能称化学工程,建议LZ找化学工业出版社出版的教材,其中有你想得实例和相应计算和图表等。这书可在图书馆找到,其第一册书号15063.3177。

给个LZ给出条件的流量
管径:15毫米
管道面积:7.0686平方毫米
流量:((7.0686/1000000)*1m/s)*3600s=0.0254m3/h
这结果远达不到LZ给出的已知液体的流量(1.2t/h/1500kg/m3)=0.8m3/h

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