1⼀(1+2)+1⼀(1+2+3)+1⼀(1+2+3+4)+十1⼀(1+2+3++50)=

请问怎么快速算呢?
2024-10-31 23:39:01
推荐回答(2个)
回答1:

1/(1+2)+1/(1+2+3)+1/(1+2+3+4)+⋯十1/(1+2+3+⋯+50)
=2/(2×3)+2/(3×4)+2/(4×5)+⋯+2/(50×51)
=2×(1/2-1/3+1/3-1/4+1/4-1/5+……+1/50-1/51)
=2×(1/2-1/51)
=1-2/51
=49/51

回答2:

先把2提出来
原式=2×(1-1/2+1/2-1/3+1/3-1/4+....+1/50-1/51)-1

=2*(1-1/51)-1
=49/51