急!求C语言高手,帮忙写个学生成绩管理小程序!通过了有分送,谢谢!题目如下:

2024-11-23 02:53:45
推荐回答(4个)
回答1:

上面的程序貌似过于简单,其实网上有很多,去网上搜,用不了在这儿花80分
我在网上找了个,参考下:

//每位学生记录包含的信息有:姓名,学号和各门功课的成绩。
//程序具有以下几项功能:求出各门课程的总分,平均分,按姓名,
//按学号寻找其记录并显示,浏览全部学生成绩和按总分由高到低显示学生信息等。

#include
#include
#include
#include "conio.h"

#define SWN 3 /* 课程数 */
#define NAMELEN 20 /* 姓名最大字符数 */
#define CODELEN 10 /* 学号最大字符数 */
#define FNAMELEN 80 /* 文件名最大字符数 */
#define BUFLEN 80 /* 缓冲区最大字符数 */
/* 课程名称表 */
char schoolwork[SWN][NAMELEN+1] = {"Chinese","Mathematic","English"};
struct record
{
char name[NAMELEN+1]; /* 姓名 */
char code[CODELEN+1]; /* 学号 */
int marks[SWN]; /* 各课程成绩 */
int total; /* 总分 */
}stu;

struct node
{
char name[NAMELEN+1]; /* 姓名 */
char code[CODELEN+1]; /* 学号 */
int marks[SWN]; /* 各课程成绩 */
int total; /* 总分 */
struct node *next; /* 后续表元指针 */
}*head; /* 链表首指针 */

int total[SWN]; /* 各课程总分 */
FILE *stfpt; /* 文件指针 */
char stuf[FNAMELEN]; /* 文件名 */

/* 从指定文件读入一个记录 */
int readrecord(FILE *fpt,struct record *rpt)
{
char buf[BUFLEN];
int i;
if(fscanf(fpt,"%s",buf)!=1)
return 0; /* 文件结束 */
strncpy(rpt->name,buf,NAMELEN);
fscanf(fpt,"%s",buf);
strncpy(rpt->code,buf,CODELEN);
for(i=0;i fscanf(fpt,"%d",&rpt->marks[i]);
for(rpt->total=0,i=0;i rpt->total+=rpt->marks[i];
return 1;
}
/* 对指定文件写入一个记录 */
void writerecord(FILE *fpt,struct record *rpt)
{
int i;
fprintf(fpt,"name code");
for(i=0;i fprintf(fpt,"%4s\n",schoolwork[i]);
fprintf(fpt,"%4s ",rpt->name);
fprintf(fpt,"%4s ",rpt->code);
for(i=0;i fprintf(fpt,"%4d",rpt->marks[i]);
fprintf(fpt,"\n");
return ;
}

/* 显示学生记录 */
void displaystu(struct record *rpt)
{
int i;
printf("\nName : %s\n",rpt->name);
printf("Code : %s\n",rpt->code);
printf("Marks :\n");
for(i=0;i printf(" %-15s : %4d\n",schoolwork[i],rpt->marks[i]);
printf("Total : %4d\n",rpt->total);
}

/* 计算各单科总分 */
int totalmark(char *fname)
{
FILE *fp;
struct record s;
int count,i;
if((fp=fopen(fname,"r"))==NULL)
{
printf("Can't open file %s.\n",fname);
return 0;
}
for(i=0;i total[i]=0;
count=0;
while(readrecord(fp,&s)!=0)
{
for(i=0;i total[i]+=s.marks[i];
count++;
}
fclose(fp);
return count; /* 返回记录数 */
}

/* 列表显示学生信息 */
void liststu(char *fname)
{
FILE *fp;
struct record s;
if((fp=fopen(fname,"r"))==NULL)
{
printf("Can't open file %s.\n",fname);
return ;
}
while(readrecord(fp,&s)!=0)
{
displaystu(&s);
printf("\n Press ENTER to continue...\n");
while(getchar()!='\n');
}
fclose(fp);
return;
}

/* 构造链表 */
struct node *makelist(char *fname)
{
FILE *fp;
struct node *p,*u,*v,*h;
if((fp=fopen(fname,"r"))==NULL)
{
printf("Can't open file %s.\n",fname);
return NULL;
}
h=NULL;
p=(struct node *)malloc(sizeof(struct node));
while(readrecord(fp,(struct record *)p)!=0)
{
v=h;
while(v&&p->total<=v->total)
{
u=v;
v=v->next;
}
if(v==h)
h=p;
else
u->next=p;
p->next=v;
p=(struct node *)malloc(sizeof(struct node));
}
free(p);
fclose(fp);
return h;
}

/* 顺序显示链表各表元 */
void displaylist(struct node *h)
{
while(h!=NULL)
{
displaystu((struct record *)h);
printf("\n Press ENTER to continue...\n");
while(getchar()!='\n');
h=h->next;
}
return;
}
/* 按学生姓名查找学生记录 */
int retrievebyn(char *fname, char *key)
{
FILE *fp;
int c;
struct record s;
if((fp=fopen(fname,"r"))==NULL)
{
printf("Can't open file %s.\n",fname);
return 0;
}
c=0;
while(readrecord(fp,&s)!=0)
{
if(strcmp(s.name,key)==0)
{
displaystu(&s);
c++;
}
}
fclose(fp);
if(c==0)
printf("The student %s is not in the file %s.\n",key,fname);
return 1;
}

/* 按学生学号查找学生记录 */
int retrievebyc(char *fname, char *key)
{
FILE *fp;
int c;
struct record s;
if((fp=fopen(fname,"r"))==NULL)
{
printf("Can't open file %s.\n",fname);
return 0;
}
c=0;
while(readrecord(fp,&s)!=0)
{
if(strcmp(s.code,key)==0)
{
displaystu(&s);
c++;
break;
}
}
fclose(fp);
if(c==0)
printf("The student %s is not in the file %s.\n",key,fname);
return 1;
}

void main()
{
int i,j,n;
char c;
char buf[BUFLEN];
FILE *fp;
struct record s;
printf("Please input the students marks record file's name: ");
scanf("%s",stuf);//输入文件名
if((fp=fopen(stuf,"r"))==NULL)
{
printf("The file %s doesn't exit, do you want to creat it? (Y/N) ",stuf);
getchar();
c=getchar();
if(c=='Y'||c=='y')
{
fp=fopen(stuf,"w");
printf("Please input the record number you want to write to the file: ");
scanf("%d",&n);
for(i=0;i {
printf("Input the student's name: ");
scanf("%s",&s.name);
printf("Input the student's code: ");
scanf("%s",&s.code);
for(j=0;j {
printf("Input the %s mark: ",schoolwork[j]);
scanf("%d",&s.marks[j]);
}
writerecord(fp,&s);
}
fclose(fp);
}
}
fclose(fp);
getchar();
/*clrscr();*/
puts("Now you can input a command to manage the records.");
puts("m : mean of the marks.");
puts("t : total of the marks.");
puts("n : search record by student's name.");
puts("c : search record by student's code.");
puts("l : list all the records.");
puts("s : sort and list the records by the total.");
puts("q : quit!");
while(1)
{
puts("Please input command:");
scanf(" %c",&c); /* 输入选择命令 */
if(c=='q'||c=='Q')
{
puts("\n Thank you for your using.");
break; /* q,结束程序运行 */
}
switch(c)
{
case 'm': /* 计算平均分 */
case 'M':
if((n=totalmark(stuf))==0)
{
puts("Error!");
break;
}
printf("\n");
for(i=0;i printf("%-15s's average is: %.2f.\n",schoolwork[i],(float)total[i]/n);
break;
case 't': /* 计算总分 */
case 'T':
if((n=totalmark(stuf))==0)
{
puts("Error!");
break;
}
printf("\n");
for(i=0;i printf("%-15s's total mark is: %d.\n",schoolwork[i],total[i]);
break;
case 'n': /* 按学生的姓名寻找记录 */
case 'N':
printf("Please input the student's name you want to search: ");
scanf("%s",buf);
retrievebyn(stuf,buf);
break;
case 'c': /* 按学生的学号寻找记录 */
case 'C':
printf("Please input the student's code you want to search: ");
scanf("%s",buf);
retrievebyc(stuf,buf);
break;
case 'l': /* 列出所有学生记录 */
case 'L':
liststu(stuf);
break;
case 's': /* 按总分从高到低排列显示 */
case 'S':
if((head=makelist(stuf))!=NULL)
displaylist(head);
break;
default: break;
}
}
}

回答2:

我的不通过了吗,你试一下不就知道了!!
#include
#include
using namespace std;
int main()
{
int a[1001][11],p,t;
int b[1001],c[11];
int m,i,j,n,g,f;
while(scanf("%d",&n))
{
scanf("%d",&m);
for(i=0;i for(j=0;j scanf("%d",&a[i][j]);
//(1)题
for(i=0;i {
b[i]=0;
for(j=0;j b[i]+=a[i][j];
}
for(j=0;j {
for(g=0;g {
if(b[g] {
t=b[g];b[g]=b[g+1];b[g+1]=t;
for(f=0;f {
p=a[g][f];a[g][f]=a[g+1][f];a[g+1][f]=p;
}
}
}
}

for(i=0;i {
for(j=0;j printf("%d ",a[i][j]);
printf("\n");
}
//(2)题
for(j=0;j {
c[j]=0;
for(i=0;i c[j]+=a[i][j];
}
double avg[11];
for(j=0;j {
avg[j]=double(c[j])/n;
}
for(j=0;j {
if(c[j]%n!=0)
printf("%.1lf ",avg[j]);
else
printf("%d ",c[j]/n);
}
printf("\n");
}
return 0;
}

回答3:

#include
#define N 4 //4个学生
#define M 5 //5门课程
void main()
{
int a[N][M],sum[N]={0};
double avg[N];
int i,j;
for(i=0;i{
printf("输入第%d个学生的成绩: \n",i+1);
for(j=0;j{
scanf("%d",&a[i][j]);
sum[i]+=a[i][j];
}
avg[i]=(double)sum[i]/M;
}
printf("总成绩为:");
for(i=0;iprintf("%4d",sum[i]);
printf("\n平均值为:");
for(i=0;iprintf("%6.2lf",avg[i]);
printf("\n");
}

回答4:

已发 126
是一个通讯录程序 分模块的 应该比较好理解
有不懂的地方可以hi我 在vc++中调试通过

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