.某地基土试验中,测得土的干容重15.7kN⼀m3,含水量19.3%,土粒比重2.71,液限28.3%,塑限16.7%, 求(1)该

2025-04-02 14:49:19
推荐回答(4个)
回答1:

Ip=Wl-Wp=11.6% IL=(w-wp)/Ip=0.220土为粉质粘土。

地基土承载力试验用于确定岩土的承载力和变形特性等,包括承载力试验,现场浸水承载力试验,黄土湿陷性试验,膨胀土现场浸水承载力试验等。

现场浸水载荷试验用以确定膨胀土地基的承载力和浸水时的膨胀变形量,黄土湿陷性试验用于测定湿陷起始压力、自重湿陷量、湿陷系数等。可采用室内压缩试验、载荷试验、试坑浸水试验。

扩展资料:

注意事项:

地基基础检测作为地基基础质量控制的最后一个环节,是检验地基基础是否达到设计要求或安全标准的重要监测方式之一。在现行建设法规的严格要求下,地基检测作为一项建设工程的前期基础工作,其重要性是不言而喻的。

由于岩土体的不确定性,在各种复杂的地质条件下,要求岩土工程勘察一丝不漏地查清整个场地的工程地质条件是有较大难度的,需要以地基检测来验证和补充勘察成果。

参考资料来源:百度百科-岩土试验

回答2:

(2)Ip=Wl-Wp=11.6%
IL=(w-wp)/Ip=0.22
0土为粉质粘土,处于硬塑状态。

回答3:

某地基土的试验中,已测得土样的干重度γd=15.7kN/m3,含水量ω=19.3%,土粒相对密度2.71,土的孔隙比为0.726。若此土样又测得ωL=28.3%,ωp=16.7%。
求:1)计算土的n和Sr。
2) 该土的塑性指数Ip、液性指数IL,并定出土的名称及状态。

回答4:

题目不完整

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