推荐回答（3个）
（1）因为：点P到两坐标轴的距离相等
所以：点P在1、3象限夹角平分线上，或者在2、4象限夹角平方线上
1、3象限夹角平分线的解析式是y=x
联立y=x和y=-1/3x+2解得x=3/2、y=3/2，点P的坐标是（3/2，3/2），所以点P在第一象限
2、4象限夹角平分线的解析式是y=-x
联立y=-x和y=-1/3x+2解得x=-3，y=3，点P的坐标是（-3，3），所以点P在第二象限
综上所述：点P所在的象限是1和2两个象限
（2）m=1
mx²-4x+4=0的根是x1=x2=2
x²-4mx+4m²-4m-5=0→x²-4x-5=0，（x-5）（x+1）=0，x1=5，x2=-1
（3）答案是45°
如图：OH是垂径，OH垂直平分AB，OH=AH=BH
所以△OHA、△OHB都是等腰直角三角形
∴∠AOB=90°
在根据：同弧所对的圆周角是圆心角度数的一半可得
∠C=45°
第一题答案应该是第一象限和第二象限，首先画出y=1/3x+2的图像，然后题中说p点到两坐标轴的距离相等，也就是y=x或y=-x，在图中画出两条直线，交点就是p点，很显然在一二两象限。
第二题答案m=1 可以利用求根公式计算，也可以根据第一个计算第二个，第一个m应该是1或者0，代入第二个0不符合，所以m=1
第三题答案应该是45度，做几何题第一就是画图审图，在圆中，∠c应该是∠aob的一半，过o点作线段AB的垂线，交点D，两个直角三角形AOD和BOD，根据勾股定理得出AD和DB相等，所以OD既是垂线又是中线，根据直角三角形斜边的中线是第三边的一半，所以∠AOB为直角，∠C为45度。
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