用VB写设计程序代码,求:s=1+(1+2)+(1+2+3)+……+(1+2+3+……+n)的值。

2025-03-25 08:53:21
推荐回答(3个)
回答1:

Function sumD(n As Integer) As Single

s = 1

i = 1

Do

i = i + 1

s = s + 1 / i

Loop Until i >= n

sumD = s

End Function

Function sumF(n As Integer) As Single

s = 0

For i = 1 To n

s = s + 1 / i

Next i

sumF = s

End Function

Private Sub Form_Click()

sum1 = sumD(100)

sum2 = sumF(100)

Print

Print "sum1="; sum1

Print "sum2="; sum2

End Sub

运行结果是:

sum1=5.187377

sum2=5.187377

扩展资料:

一、print是一个打印输出语句。

不带输出项的print即为输出一个空行,如果之前的print语句输出项的最后用了诸如“,”或“;”,则表示其输出是在同一行上。其后面的空的print语句用来消除前面的print语句一直在同一行上输出的效果,使其后面的输出是在下一行。

如:Print()

二、print(DOS命令)

打印文本文件。

回答2:

Private Sub Command1_Click()

n = CInt(InputBox("N="))

Print "N="; n

For i = 1 To n

t = t + i

s = s + t

Next i

Print "Sum="; s

End Sub

回答3:

Private Sub Command1_Click() Dim n, s Dim i, j n = Val(InputBox("请输入数据:")) For i = 1 To n For j = 1 To i s = s + j Next j Next i Print s End Sub