已知cos(a加b)=负5分之1,cos(a减b)=5分之3,求tana和tanb的值,要过程,求

2025-03-17 07:23:39
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回答1:

cos(A+B)=cosAcosB-sinAsinB
cos(A-B)=cosAcosB+sinAsinB
cos(A+B)+cos(A-B)=2cosAcosB(1)
cos(A+B)-cos(A-B)=-2sinAsinB(2)
(2)/(1)
-tanAtanB=(-2/5)/(4/5)=-1/2
tanAtanB=1/2