三角函数的实二元函数是什么?

复变函数与积分变换里面的内容
2025-04-02 20:30:12
推荐回答(1个)
回答1:

F =@(x) [1.3-((tan(x(1))+2/(x(2)*cos(x(1)))*0+0.4*log(1-5*0/(x(2)*cos(x(1))))));
3-((tan(x(1))+2/(x(2)*cos(x(1)))*+0.4*log(1-5*5/(x(2)*cos(x(1))))))];
fsolve(@(x)F(x),rand(2,1))