已知如图所示,在平行四边形abcd中,e,f分别是ab,cd的中点,求证af=ce

0.0
2024-12-04 03:43:04
推荐回答(4个)
回答1:

因为平敏厅行四边锋耐形桥基隐ABCD
所以AB=CD,AD=BC,∠D=∠B
DF=BE=1/2AB
AF^2=AD^2+DF^2-2ADDFcosD
CE^2=B^2+BE^2-2BCBEcosB
所以AF=CE

回答2:

为E,F是AD,BC中雀轮点
AE=DE,BF=CF
因为四边形ABCD是平行四边形
AD=∥⑴BC
所以AE=FC(=得) ∠EAF=∠BFA(∥⑴得)
所以四边形AFCE是平行四边形
所以AF∥EC⑵碧高
∠AFB=∠ECB
所以∠EAF=∠ECB
同理∠BGF=∠FHC
在三角形AGE,CHF中
EAG=FCH(角)
AGE=CHF
AE=CF
AGE≌CHF
EG=FH
同理DEH≌BGF
GF=EH
所以四边形EGFH是平行四边形

这是我自己画悔岁尺的图,如字母有对不上的,请自行修改

回答3:

∵四边形ABCD为平行四边形,
∴AB∥CD,AB=CD,
又∵E、F是AB、CD的中租谨纯点,
∴AE=1/2AB,CF=1/2CD,
∴AE=CF,AE∥CF,
∴四边形AECF是平行四边形,
∴AF=CE.
(证晌袜法二):
∵四边形ABCD为平行四边形,
∴AB=CD,AD=BC,∠B=∠D,
又∵E、F是AB、CD的中弊咐点,
∴BE=1/2AB,DF=1/2CD,
∴BE=DF,
∴△ADF≌△CBE(SAS),
∴AF=CE.

回答4:

在平行四边形睁困腔abcd中,dc=ab,dc∥ab
∴fc∥悉衫ae
∵e,f分别是ab,cd的中点且尺兄dc=ab
∴fc=ae
∴四边形abcd是平行四边形(一组对边分别平行且相等)
∴af=ce

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