汇编问题,急急急

2025-03-23 14:23:22
推荐回答(2个)
回答1:

已经改正
data segment
string1 db 'please input the string$'
string2 db 'the number of the digity is:$'
string3 db 'the number of the char is:$'
idchar db 10 dup(?)
iddigity db 10 dup(?)
digity db 0
char db 0
data ends

code segment
assume cs:code,ds:data
start:
mov ax,data
mov ds,ax

mov cx,10d
lea di,idchar
lea si,iddigity

mov ah,09h
lea dx,string1
int 21h

call crlf
input1:
mov ah,01h
int 21h

cmp al,30h
jb input1
cmp al,39h;这应该为比较指令,不应该为减法指令,否则会破坏AL值
ja charinc

digity1:
inc digity
mov byte ptr[si],al
inc si
jmp input

charinc:
cmp al,41h;判断是否为大写字母
jb input1
cmp al,5ah
jbe input2
cmp al,61h;判断是否为小写字母
jb input1
cmp al,7ah
ja input1
input2:
inc char
mov byte ptr[di],al
inc di
input:
loop input1

call crlf

lea dx,string2
mov ah,09h
int 21h

mov dl,digity
add dl,30h
mov ah,02h
int 21h

call crlf

mov cl,digity
lea bx,iddigity

outputdigity:
mov ah,02h
mov dl,byte ptr[bx]
int 21h
inc bx
dec cl
jne outputdigity

call crlf

mov ah,09h
lea dx,string3
int 21h

mov ah,02h
mov dl,char
add dl,30h
int 21h

call crlf

lea bx,idchar
mov cl,char
outputchar:

mov ah,02h
mov dl,byte ptr[bx]

int 21h
inc bx
dec cl
jne outputchar
exit:
mov ah,1
int 21h
mov ah,4ch
int 21h

crlf proc near
push ax
push dx
mov dl,0ah
mov ah,02h
int 21h

mov dl, 0dh
int 21h
pop dx
pop ax
ret
crlf endp
code ends
end start

回答2:

这样没法检查的。一般高手不会像这样修改程序
建议:把每个代码段想要执行的功能注释出来。这样修改起来就有了方向。也许,你自己也能把问题找出来了。

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