0.05mol⼀L PH7.8的磷酸缓冲液(PBS)的配制方法 (含0.1mmol⼀L的EDTA)

2025-03-11 11:26:35
推荐回答(2个)
回答1:

PH=PKa2-lg[H2PO4^-]/[HPO4^2-]
7.8=7.2-lg[H2PO4^-]/[HPO4^2-]
lg[H2PO4^-]/[HPO4^2-]=-0.6
[H2PO4^-]/[HPO4^2-]=4/1
如果配制一升溶液,那么
需要无水磷酸二氢钠的质量是120×0.05=6克
需要氢氧化钠的质量是40×0.05×1/4=0.5克
需要EDTA的质量是0.1×292/1000=0.03克
将以上三种试剂加水配制成1升溶液即可.

回答2:

0.05mol/L PBS(磷酸缓冲液Phosphate Buffer Solution,PBS)的配制:

甲液:0.05mol/L Na2HPO4溶液 :称取磷酸氢二钠9.465g 7.099g,加蒸 馏水至1000ml ;
乙液:0.05mol/L KH2P04溶液: 称取磷酸二氢钾, 9.07g 6.803g,加蒸馏水至1000m1。
将甲乙液分装在棕色瓶内,于4℃冰箱中保存,用时甲、乙两液各按不同比例混合,即可得所需pH的缓冲液,见下表:

pH 甲液ml 乙液mI
5.29 2.5 97.5
5.59 5.0 95.0
5.91 10.0 90.0
6.24 20.0 80.0
6.47 30.0 70.0
6.64 40.0 60.0
6.81 50.0 50.0
6.98 60.0 40.0
7.17 70.0 30.0
7.38 80.0 20.0
7.73 90.0 10.0
8.04 95.0 5.0
你要配制pH=7.8的PBS,可用甲91.5ml、乙液8.5ml混合即可。

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