二元一次解方程:(1)3x눀-1=0 (2)x(2x+3)=5(2x+3)(3)x눀-4x-2=0 (4)2x눀-5x+1=0

(1)3x눀-1=0 (2)x(2x+3)=5(2x+3)(3)x눀-4x-2=0 (4)2x눀-5x+1=0
2024-12-03 21:22:28
推荐回答(1个)
回答1:

3x²-1=0
3x²=1
x²=1/3
x=±√(1/3)

x(2x+3)=5(2x+3)
x=5

x²-4x-2=0
x²-4x+2-4=0
(x-2)²=4
x-2=±4
x=2±4
x1=6 x2=-2

2x²-5x+1=0
△=(-5)²-4×2×1=17
x=(5±√17)/(2×2)
x1=(5+√17)/4 x2=(5-√17)/4