对Y=2(X-1)^4,Y=sin^2(3X+1) Y=e^tanx^2,求导,

2025-03-22 04:50:25
推荐回答(1个)
回答1:

Y=2(X-1)^4

y'=2*4(x-1)^3
=8(x-3)^3

Y=sin^2(3X+1)

y'=2sin(3x+1)*cos(3x+1)*3
=6sin(3x+1)cos(3x+1)
=3sin(6x+2)

Y=e^tanx^2

y\=e^tanx^2 *(secx^2)^2 *2x
=2xe^tanx^2(secx^2)^2