[化学-选修3:物质结构与性质]硅是重要的半导体材料,构成了现代电子工业的基础.请回答下列问题:(1)

2025-04-06 15:22:16
推荐回答(1个)
回答1:

(1)硅原子核外有14个电子,其基态原子的核外电子排布式为1s22s22p63s23p2 ,对应能层分别别为K、L、M,其中能量最高的是最外层M层,该能层有s、p、d三个能级,s能级有1个轨道,p能级有3个轨道,d能级有5个轨道,所以共有9个原子轨道,硅原子的M能层有4个电子(3s23p2);
故答案为:M;9;4;
(2)硅元素在自然界中主要以化合态(二氧化硅和硅酸盐)形式存在,
故答案为:二氧化硅
(3)硅晶体和金刚石晶体类似都属于原子晶体,硅原子之间以共价键结合.在金刚石晶体的晶胞中,每个面心有一个碳原子(晶体硅类似结构),则面心位置贡献的原子为 6×

1
2
=3个;
故答案为:共价键;3;
(4)Mg2Si和NH4Cl在液氨介质中反应制得SiH4、NH3和MgCl2,方程式为:Mg2Si+4NH4Cl=SiH4+4NH3+2MgCl2,故答案为:Mg2Si+4NH4Cl=SiH4+4NH3+2MgCl2
(5)①烷烃中的C-C键和C-H键大于硅烷中的Si-Si键和Si-H键的键能,所以硅烷中Si-Si键和Si-H键的键能易断裂,导致长链硅烷难以生成,
故答案为:C-C键和C-H键较强,所形成的烷烃稳定,而硅烷中Si-Si键和Si-H键的键能较低,易断裂,导致长链硅烷难以生成;
②键能越大、物质就越稳定,C-H键的键能大于C-O键,故C-H键比C-O键稳定,而Si-H键的键能远小于Si-O键,所以Si-H键不稳定而倾向与形成稳定性更强的Si-O键;
故答案:C-H键的键能大于C-O键,C-H键比C-O键稳定.而Si-H键的键能却远小于Si-O键,所以Si-H键不稳定而倾向于形成稳定性更强的Si-O键;
(6)硅酸盐中的硅酸根(SiO
 
)为正四面体结构,所以中心原子Si原子采取了sp3杂化方式;
故答案为:sp3 
根据图(b)的一个结构单元中含有1个硅、3个氧原子,化学式为SiO32-
故答案为:1:3;SiO32-

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