85问答库 > 有一内阻为1k欧姆，满偏电流为50uA的电流表，现要改装成量程为1mA的电流表，需要并联多大电阻？

有一内阻为1k欧姆，满偏电流为50uA的电流表，现要改装成量程为1mA的电流表，需要并联多大电阻？

帮帮忙，急呀
2025-03-16 03:41:58
推荐回答（1个）
回答1：

改装成电流表并联一个电阻分流 I=I1+I2=50*10^-6+I2=1*10^-3 I2=950*10^-6A U=I1*R1=1000*50*10^-6=50*10^-3V I2R2=950*10^-6*R2=50*10^-3 解得R2=52.63欧姆

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