求20道初三物理电学难题以及详细的解答过程...

2024-12-28 12:32:03
推荐回答(5个)
回答1:

去多买点书不就行了..
何必那么麻烦呢.......
还有
初三下学期基本都是复习,到时候你会做到很多考卷,做到各地的中考题.题目多得绝对足够了.因为每天基本都是做考卷 = =
所以
现在不用很急的,把你以前做的先弄懂吧.先搞清楚基础的
难道现在做了20道以后就什么都会了吗?

回答2:

没有题我怎么给你解答啊
把电学题发上来,包括图片
我来给你解决

回答3:

1.一段铜线的电阻为R,两端电压为U,通过电流强度为I,下列说法中正确的是〔 〕
A.R由铜线的长度和横截面积决定
B.R的大小与U有关
C.铜线的电阻对电流通过有阻碍作用
D.R的大小与I无关
2.两个电阻值完全相等的电阻,若并联后的总电阻是10欧姆,则将它们串联的总电阻是〔 〕
A.5欧姆 B.10欧姆
C.20欧姆 D.40欧姆
3.一条导线的电阻是R,把它对折分成等长的两段后,再把这两段并联起来使用,这时电阻 是〔〕
A. R/4 B.R/2 C. R/2
4.4个电阻,电阻值都是R,把它们并联起来,总电阻是〔 〕
A.4R B.R/4 C.4/R D.2R
5.两条长度相等、截面积不等的同种材料制成的电阻丝,串联在电路中,则粗电阻丝〔 〕
A.电流强度较大 B.电流强度较小
C.电压较大 D.电压较小
6.下面四对并联电阻,总电阻最小的是 〔 〕
A.两个4Ω B.一个4Ω,一个6Ω
C.一个1Ω,一个8Ω D.一个2Ω,一个7Ω
7.今有三个电阻,它们的电阻值分别是a欧、b欧、c欧,其中a>b>c,当把它们并联相接,总电阻为R,它们的大小关系,下列哪个判断是正确的〔 〕
A.cC.R可能等于b D.R8.两个电阻值相等的电阻,每个电阻的电阻值为R。现将其中一个电阻增大,另一个电阻减小,则并联后的总电阻将〔 〕
A.大于R B.小于R
C.仍等于R D.无法判定
9.有一条电阻线,在其两端加1伏特电压时,测得电阻值0.5欧姆,如果在其两端加10伏特电压时,其电阻值应为〔 〕
A.0.5欧姆 B.5欧姆
C.0.05欧姆 D.20欧姆
10.电阻R1的阻值比电阻R2小,把它们并联后,总电阻[ 〕
A.既小于R1又小于R2 B.既大于R1又大于R2
C.小于R2而大于R1 D.等于R1与R2之和
11.两个完全相同的电阻,它们串联的总电阻是并联的总电阻的 〔〕

12.修理电器需要一只150欧姆的电阻,但只有电阻值分别为100欧姆、200欧姆、600欧姆的电阻各一只,可代用的办法是〔〕
A.把200欧姆的电阻与600欧姆的电阻串联起来
B.把100欧姆的电阻与200欧姆的电阻串联起来
C.把100欧姆的电阻与200欧姆的电阻并联起来
D.把200欧姆的电阻与600欧姆的电阻并联起来
13.导体两端的电压是4伏特,通过的电流强度是0.8安培,如果使导体两端的电压增加到6伏特,那么导体的电阻和电流强度分别是〔〕
A.5欧姆,1.2安培 B.5欧姆,2安培
C.7.5欧姆,0.8安培 D.12.5欧姆,0.8安培
14.图44中定电阻R1、R2和滑动变阻R串联,R1和R2两端的电压分别为U1和U2,当滑动变阻器的滑动片P向右滑动过程中〔〕

A. U1变小,U1/U2也变小 B. U1变小,U1/U2不变
C. U1不变,U1/U2变小 D. U1不变,U1/U2也不变
15.如图45所示的电路,U=24伏特,安培表的示数为1.2安培,伏特表的示数为12伏特,则R1的电阻值为 〔 〕
A.8欧姆 B.6欧姆
C.5欧姆 D.10欧姆
1.ACD 2.D 3.A 4.B 5.D
6.C 7.D 8.B 9.A 10.A
11.D 12.D 13.A 14.B 15.D
16.C 17.C 18.BC 19.A 20.C

回答4:

er

回答5:

http://www.pep.com.cn/
这上面有很多中考题,我懒得发上来,而且发上来太不完整了,你自己去看看吧,无需下载,可以复制,可以打印

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