3x^2+5xy-2y^2+x+9y-4 =3x^2+(5y+1)x-(2y^2-9y+4) =3x^2+(5y+1)x-(y-4)(2y-1) =(3x-y+4)(x+2y-1) 十字交叉
3x^2+5xy-2y^2+x+9y-4 =(x+2y)(3x-y)+x+9y-4 =(x+2y-1)(3x-y+4).
3x -y 4 x 2y -1 双十字因式分解~~~ 得: 3x^2+5xy-2y^2+x+9y-4 =(3x-y+4)(x+2y-1)