镁与铝与稀盐酸反应的剧烈程度不同,能否说明金属的活动性顺序

2025-03-15 16:16:09
推荐回答(3个)
回答1:

能够说明,但要与同浓度的盐酸反应时,镁与稀盐酸反应更剧烈,可以说明镁比铝更活泼。

1、原理:
Mg+2HCl=MgCl2+H2
2Al+6HCl=2AlCl3+3H2
与同浓度的稀盐到反应时,镁反应更剧烈,说明镁更易失电子,故镁比铝更活泼。

2、金属的活动性判断方法:
(1)根据金属活动顺序表。
(2)金属单质与水或酸反应置换出氢的难易判断 :
与水或酸反应越易、越剧烈的金属单质,其原子越易失电子,该金属活泼性越强。
(3)依电化学中电极来判断 :
原电池中,负极金属是电子流出的极,正极金属是电子流人的极,其还原性:负极>正极,故活泼性负极金属大于正极金属。
(4)根据物质间的置换反应来判断:
活泼性强的金属能将活泼性弱的金属从其盐溶液中置换出来。
(5)根据金属阳的离子氧化性:
金属阳离子的氧化性越强,其对应的金属单质活泼性越弱。

回答2:

反应的剧烈程度不但与活泼性有关,还与温度、颗粒度等有关,按他们反应剧烈程度来判断其活动性顺序需要好多前提的

回答3:

不行,反应放热,对反应速率有影响

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