求微分方程想x^2dy+(3-2xy)dx=0的通解

2024-11-27 22:27:59
推荐回答(1个)
回答1:

........这个 答案是:
y[x]=(3*x+C1)/x^2

我用Mathematica 算的
DSolve[y'[x] == (3 - 2 x y[x])/x^2, y[x], x]
结果是:
{{y[x] -> 3/x + C[1]/x^2}}

MATLAB 代码是:
dsolve('Dy=(3-2*x*y)/x^2','x')
答案:
ans =

(3*x+C1)/x^2