高分求一个C语言的五子棋程序

2024-12-02 05:21:44
推荐回答(4个)
回答1:


//但是这些代码由于编译器的原因,在TC下仍无法运行。请使用VC。
#include
#include
#include
#include

int ChessData[15][15] ={0};
int GuangbiaoData[2]={8,8};
int ChessStepData[255][2]={0};

void gotoxy(int x, int y) //gotoxy在TC中是在一个系统自带的函数,但是在VC中没有这个函数,所以在网上找到了这个函数以实现同样的功能。
//只有这一个函数是网上找的,别的全部我自己写的。
{
COORD c;
c.X=x-1;
c.Y=y-1;
SetConsoleCursorPosition (GetStdHandle(STD_OUTPUT_HANDLE), c);
}

void GotoChess(int x,int y)
{
x=3*x-2;y=2*y-1;
gotoxy(x,y);
}

void Move(int MoveData) //输入参数为用户输入的方向(1表示上,2表示下,3表示左,4表示右)
{
switch (MoveData)
{
case 1:GuangbiaoData[1]-=1;break;
case 2:GuangbiaoData[1]+=1;break;
case 3:GuangbiaoData[0]-=1;break;
case 4:GuangbiaoData[0]+=1;break;
default:printf("Move函数出错");
}
GotoChess(GuangbiaoData[0],GuangbiaoData[1]);
}

int Get(int *data) //该函数的功能是用户的按键,并转化为01234567(0表示输入错误,1表示上,2表示下,3表示左,4表示右,5表示落子,6表示悔棋,7表示退出。)
{ //并返回输入的用户号码(共同键返回3),错误则返回0
int temp;

B: temp=getch();
if (temp==224)
{
temp=getch();
switch (temp)
{
case 72:*data=1;break;
case 80:*data=2;break;
case 75:*data=3;break;
case 77:*data=4;break;
default:goto B;
}
return 2;
}
else
{
switch (temp)
{
case 'w':
case 'W':*data=1;return 1;break;
case 's':
case 'S':*data=2;return 1;break;
case 'a':
case 'A':*data=3;return 1;break;
case 'd':
case 'D':*data=4;return 1;break;
case 13 :*data=5;return 2;break;
case 32 :*data=5;return 1;break;
case 8 :*data=6;break;
case 27 :*data=7;break;
default:*data=0 ;return 0;break;
}
return 3;
}
}
void MoveToEnd()
{
gotoxy(1,30);
}
int LogicBeOut(int a,int b)
{
if (a==-1||a==15||b==-1||b==15) return 1;
else return 0;
}
int win(int v)
{
int i=1,j=1,a=0,b=0;
while (ChessData[a=GuangbiaoData[0]-i-1][b=GuangbiaoData[1]-i-1]==v*2&&!LogicBeOut(a,b)) i++;
while (ChessData[a=GuangbiaoData[0]+j-1][b=GuangbiaoData[1]+j-1]==v*2&&!LogicBeOut(a,b)) j++;
if (i+j-1>=5) return 1;

i=1,j=1,a=0,b=0;
while (ChessData[a=GuangbiaoData[0]+i-1][b=GuangbiaoData[1]-i-1]==v*2&&!LogicBeOut(a,b)) i++;
while (ChessData[a=GuangbiaoData[0]-j-1][b=GuangbiaoData[1]+j-1]==v*2&&!LogicBeOut(a,b)) j++;
if (i+j-1>=5) return 1;

i=1,j=1,a=0,b=0;
while (ChessData[a=GuangbiaoData[0]-i-1][b=GuangbiaoData[1]-1]==v*2&&!LogicBeOut(a,b)) i++;
while (ChessData[a=GuangbiaoData[0]+j-1][b=GuangbiaoData[1]-1]==v*2&&!LogicBeOut(a,b)) j++;
if (i+j-1>=5) return 1;

i=1,j=1,a=0,b=0;
while (ChessData[a=GuangbiaoData[0]-1][b=GuangbiaoData[1]-i-1]==v*2&&!LogicBeOut(a,b)) i++;
while (ChessData[a=GuangbiaoData[0]-1][b=GuangbiaoData[1]+j-1]==v*2&&!LogicBeOut(a,b)) j++;
if (i+j-1>=5) return 1;

return 0;
}

void NewShow() //新棋局的开始
{
int i,j;
for (i=0;i<15;i++)
for (j=0;j<15;j++)
ChessData[i][j]=0;
system("cls");
for (i=1;i<=29;i++)
{
for (j=1;j<=43;j++)
if(i%2==1) printf("-");
else if (j%3==1) printf("|");
else printf(" ");
printf("\n");
}
GuangbiaoData[0]=8;GuangbiaoData[1]=8;
MoveToEnd();
printf("现在请用户1下棋 \n");
printf("用户1使用 w,s,a,d移动光标,空格键落子\n");
printf("用户2使用各方向键移动光标,回车键落子\n");
printf("按下Backspace键悔棋,按下esc返回主菜单\n");
GotoChess(8,8);
}

int BeOut(int data)
{
int Xiuzheng[2],New[2];
switch (data)
{
case 1:Xiuzheng[0]=0;Xiuzheng[1]=-1 ;break;
case 2:Xiuzheng[0]=0;Xiuzheng[1]=1;break;
case 3:Xiuzheng[0]=-1;Xiuzheng[1]=0;break;
case 4:Xiuzheng[0]=1;Xiuzheng[1]=0 ;break;
case 5:Xiuzheng[0]=0;Xiuzheng[1]=0 ;break;
default:printf("BeOut函数出错");
}
New[0]=GuangbiaoData[0]+Xiuzheng[0];
New[1]=GuangbiaoData[1]+Xiuzheng[1];
if (New[0]>15||New[0]<1||New[1]>15||New[1]<1) return 1;
else return 0;
}

void UserChoose(int * choice)
{
system("cls");
printf("________________________________________________________________________________");
printf("________________________________________________________________________________");
printf(" $1.单人游戏 ");
printf(" 2.双人游戏 ");
printf(" 3.退出游戏 ");
printf(" 4.游戏帮助 ");
printf("________________________________________________________________________________");
printf("________________________________________________________________________________");
printf(" ");
printf(" 开心五子棋 ");
printf(" ");
printf(" 出品人:张云聪 ");
printf(" 学号:067108034 ");
printf(" 指导老师:邵艳玲 ");
printf(" ");
printf(" ");
printf(" 温馨提示,游戏时请把窗口最大化,以达到最佳效果 ");
printf("________________________________________________________________________________");
int temp=0,i=0;
do
{
if ((temp=getch())==224)
{
temp=getch();
if (temp==72&&i!=0)
{
gotoxy(34,3+i);
printf(" ");
i--;
gotoxy(34,3+i);
printf("$");
gotoxy(0,0);
}
else if(temp==80&&i!=3)
{
gotoxy(34,3+i);
printf(" ");
i++;
gotoxy(34,3+i);
printf("$");
gotoxy(0,0);
}
}

else if (temp==13) {*choice=i+1;return;}
else if (temp==27) {*choice=3;return;}
else if (temp=='1'||temp=='2'||temp=='3'||temp=='4') {*choice=temp-48;return;}

}while(1);
}

int CannotDo(int v1,int v2,int MoveData,int choice) //第一个输入值为按键的用户号,第二个是本应该按键的用户号,第三个为按下键的对应值,第四个键代表游戏模式。
{
if (v1==3) return 0; //如果用户输入的为共用按键,则CannotDo为假

else if (v1==0) return 1;//如果用户输入错误,则CannotDo为真
else if (v1!=v2&&choice==2) return 1; //如果不该此用户输入,而用户进行了输入,则CannotDo为真

if (BeOut(MoveData)) return 1; //如果移动出边界则CannotDo为真
return 0;
}

int CannotLuozi() //判断是否可以落子。
{
if (ChessData[GuangbiaoData[0]-1][GuangbiaoData[1]-1])
return 1;
else return 0;
}

int luozi(int v) //玩家v落子。
{
ChessData[GuangbiaoData[0]-1][GuangbiaoData[1]-1]+=v*2;
if (v==1) printf("O");
else if (v==2) printf("X");
else printf("luozi函数出错");
if (win(v)) {MoveToEnd();printf("玩家%d获得了胜利! \n",v);for (int i=1;i<=240;i++) printf(" ");GotoChess(GuangbiaoData[0],GuangbiaoData[1]);getch();return 1;}
MoveToEnd();
printf("现在请用户%d下棋 ",v%2+1);
GotoChess(GuangbiaoData[0],GuangbiaoData[1]);
return 0;
}

void HuiQi(int step) //输入的是当前的要悔的棋是第几步
{
GuangbiaoData[0]=ChessStepData[step-1][0];
GuangbiaoData[1]=ChessStepData[step-1][1];
ChessData[GuangbiaoData[0]-1][GuangbiaoData[1]-1]=0;

GotoChess(GuangbiaoData[0],GuangbiaoData[1]);
printf("-");
MoveToEnd();
printf("现在请用户%d下棋 ",(step+1)%2+1);
GotoChess(GuangbiaoData[0],GuangbiaoData[1]);
}

int DataGetAndChoose(int choice)
{
int MoveData=0,i=0,temp; //MoveData 0表示不可移动,1表示上,2表示下,3表示左,4表示右,5表示落子,6表示悔棋,7表示退出。
while(1)
{
loop: while (temp=Get(&MoveData),CannotDo(temp,i%2+1,MoveData,choice));
switch (MoveData)
{
case 1:
case 2:
case 3:
case 4:Move(MoveData);break;
case 7:return 0;
case 6:
if (i==0) {MoveToEnd();printf("现在无法悔棋 ");GotoChess(GuangbiaoData[0],GuangbiaoData[1]);}
else HuiQi(i--);
break;
case 5:
if (CannotLuozi()) goto loop;
if(luozi(i%2+1)) return 0;
ChessStepData[i][0]=GuangbiaoData[0];
ChessStepData[i][1]=GuangbiaoData[1];
i++;
break;
default:printf("DataGetAndChoose函数出错");break;
}
}
return 1;
}

void ShowHelp()
{
system("cls");
printf("********************************************************************************");
printf("********************************************************************************");
printf("****** 单人游戏供用户一个人自己与自己下棋研究棋局之用 ******");
printf("****** 双人游戏中,用户1使用wsad控制方向,按空格落子 ******");
printf("****** 用户2按方向键控制方向,回车键落子 ******");
printf("****** 游戏过程中按esc返回主菜单 ******");
printf("****** 游戏过程中退格键悔棋 ******");
printf("****** 双人模式中某人下棋时,另一个用户无法控制光标与落子 ******");
printf("****** ******");
printf("****** 帮助 ******");
printf("****** 按任意键返回 ******");
printf("********************************************************************************");
printf("********************************************************************************");
getch();
}

int main()
{
int choice=0;
system("color 2b");
choose: UserChoose(&choice);
if (choice<1||choice>4) goto choose;
if (choice==3) {gotoxy(1,18);
printf("\n谢谢您的使用,再见 "); getch();return 0;}
if (choice==4) {ShowHelp(); goto choose;}
NewShow();
DataGetAndChoose(choice);
main();
return 0;

回答2:

我传给你C语言的。,请查收把

回答3:

地下代码可以,VC 编译时改变变量位置即可

回答4:

http://hi.baidu.com/3bian/blog/item/69e21fef713c08f1b2fb95b6.html
我的空间,以前写的

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