求极限当x趋近于0时(e^3x-e^2x-e^x)⼀대√{(1-x)(1+x)}-1

2024-11-21 00:13:06
推荐回答(2个)
回答1:

(1-x^2)^(1/3)=1-1/3*x^2
分漏液绝子=e^2x*(e^x-1)-e^x+1=(1+2x)*x-x=2x^2
极限埋雀=2/返姿(-1/3)=-6

回答2:

原式=lim(x->凯腊枣0) {[e^(2x)-1]*(e^x-1)}/盯拆[(1-x^2)^(1/3)-1]
=lim(x->0) (2x*x)/局埋[(-x^2)*(1/3)]
=-6