∫cos2x⼀cosx^2sinx^2dx不定积分多少啊?

2024-11-03 03:33:55
推荐回答(1个)
回答1:

∫cos2x/cosx^2sinx^2dx
=2∫cos2x/(sin2x)^2dx
=∫1/(sin2x)^2dsin2x
=-1/sin2x+C