85问答库 > 当m取何值时,方程组x-2y=0,2x+my=4的解(1)是正数(2)是正整数

当m取何值时,方程组x-2y=0,2x+my=4的解(1)是正数(2)是正整数

m可以为任意值
2025-04-07 11:06:32
推荐回答（2个）
回答1：

先把m看成系数解这个方程组

2x-4y=0
2x+my=4

下面减上面

(m+4)y=4
y=4/(m+4)
x=2y=8/(m+4)

要使解是正数，那么m+4>0,m>-4

要使解是正整数，那么m+4要是4,8的约束，所以m=-2或m=0~~

回答2：

(1)x-2y=0
得x=2y
带入2x+my=4
得y=4/（m+4）
因为解为正数所以x>0y>0
得m>-4
(2)因为解为正整数
凑解
m=-3 m=-2 m=0

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