85问答库 > .某有机化合物A的相对分子质量大于100,小于l30。经分析得知,其中碳和氢的质量分数

.某有机化合物A的相对分子质量大于100,小于l30。经分析得知,其中碳和氢的质量分数

2025-04-01 14:11:10
推荐回答（1个）
回答1：

计算可得其氧的质量分数为53.34%，∵100＜M（A）＜130，∴53.34＜M（O）＜69.342，∴3.3＜N（O）＜4.3，得N（O）=4，∴M（A）=120。∴M（碳和氢）=56.为C4H8，A分子式为C4H8O4，则根据不饱和度可计算得，碳氧双键最多为1个

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