(1)完成下列反应的化学方程式①环己烷与溴的四氯化碳溶液在光照条件下反应生成一溴取代产物:______.

2024-12-02 02:48:37
推荐回答(1个)
回答1:

(1)①环己烷与溴的四氯化碳溶液在光照条件下发生取代反应生成一溴环己烷和溴化氢,反应为+Br2
光照
+HBr,
故答案为:+Br2
光照
+HBr;
②含C=C,能发生加聚反应生成聚2-甲基-1,3-丁二烯,反应为n CH2=C(CH3)-CH=CH2
一定条件

故答案为:n CH2=C(CH3)-CH=CH2
一定条件


(2)该物质为某芳香烃A,含苯环,104-6×12=30,只有C、H元素,则
30
12
=2…6,分子中共8个C,所以分子式为C8H8,为苯乙烯,
①苯乙烯的结构简式为CH2=CH-C6H5,故答案为:CH2=CH-C6H5
②苯环与双键均为平面结构,且直接相连,则碳原子是处于同一平面,故答案为:是;
(3)支链上共含有3个C原子,说明主链至少含有4个C原子,满足要求的烯烃的结构简式为CH2=CH(CH3)C(CH33,名称为2,3,3-三甲基-1-丁烯,
故答案为:CH2=CH(CH3)C(CH33;2,3,3-三甲基-1-丁烯.

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