二次函数一般式化为顶点式,求过程详解

2024-11-29 16:46:32
推荐回答(2个)
回答1:

1)一般式:y=ax2+bx+c
(a,b,c为常数,a≠0),则称y为x的二次函数。顶点坐标(-b/2a,(4ac-b^2)/4a)
  (2)顶点式:y=a(x-h)2+k或y=a(x+m)^2+k(a,h,k为常数,a≠0).

(3)交点式(与x轴):y=a(x-x1)(x-x2)

  (4)两根式:y=a(x-x1)(x-x2),其中x1,x2是抛物线与x轴的交点的横坐标,即一元二次方程ax2+bx+c=0的两个根,a≠0.

  说明:

(1)任何一个二次函数通过配方都可以化为顶点式y=a(x-h)2+k,抛物线的顶点坐标是(h,k),h=0时,抛物线y=ax2+k的顶点在y轴上;当k=0时,抛物线a(x-h)2的顶点在x轴上;当h=0且k=0时,抛物线y=ax2的顶点在原点.

  (2)当抛物线y=ax2+bx+c与x轴有交点时,即对应二次方程ax2+bx+c=0有实数根x1和x2存在时,根据二次三项式的分解公式ax2+bx+c=a(x-x1)(x-x2),二次函数y=ax2+bx+c可转化为两根式y=a(x-x1)(x-x2).

回答2:

二次函数
y=ax^2+bx+c
---一般式.
用配方法化为"顶点"式:
y=a(x+b/2a)^2-(b^2/4a)+c.
y=a(x+b/2a)^2-(b^2-4ac)/4a.
---这就是所谓的"顶点"式.
顶点坐标为[-b/2a.-(b^2-4ac)/4a]

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