多元复合函数求二阶导

2024-11-17 08:12:14
推荐回答(1个)
回答1:

dy/dx=(xexp(-x))'f'(xexp(-x))=(1-x)exp(-x)f'(xexp(-x)),
d^2y/dx^2=((1-x)exp(-x))'f'(xexp(-x))+(1-x)exp(-x)(xexp(-x))'f''(xexp(-x))
=(x-2)exp(-x)f'(xexp(-x))+(1-x)^2*exp(-2x)f''(xexp(-x)).