y=(2x+3)/(x-1)=[2(x-1)+2+3]/(x-1)=2+5/(x-1)x＜1，∴5/(x-1)＜0，∴y＜2或∵x＜1，x-1≠0，变换得y(x-1)=2x+3，即x=(3+y)/(y-2)＜1即(3+y)/(y-2)-1=5/(y-2)＜0，∴y＜2
