①根据燃烧热概念,结合热化学方程式,2H2(g)+O2(g)=2H2O (l)△H=-571.6kJ/mol,氢气的燃烧热为:H2(g)+O2(g)=H2O (l)△H=-285.8kJ/mol,所以氢气的燃烧热为285.8KJ/mol,故答案为:-285.8KJ/mol;
②(1)CO(g)+2H2(g)?CH3OH(g)△H=-90.8kJ/mol,(2)H2(g)+O2(g)=H2O(g)△H=-241.8kJ/mol;
(2)×2-(1)得到:CH3OH(g)+O2(g)?CO(g)+2H2O(g)△H=-392.8 kJ/mol,
故答案为:-392.8 kJ/mol.