推荐回答(5个)
湖北省08年的高考大纲还没有出台,由于湖北省是自主出题的省份,所以建议你看看近年湖北省高考试题。你累看看这个对你是否有用:
武汉市2008届高中毕业生二月调研测试 试题参考答案及评分细则
http://www.whjy.net/whjy/jydt/77541.shtml
华师一附中名师解析二月调考
http://www.whjy.net/whjy/jydt/77660.shtml
物理:重在考基础赋分更合理
http://www.whjy.net/whjy/jydt/77658.shtml
化学:注重综合性 突出推断题
http://www.whjy.net/whjy/jydt/77657.shtml
生物:区分度较强 注重抓主干
http://www.whjy.net/whjy/jydt/77655.shtml
武汉教育信息网:
http://www.whjy.net/
这个网站里还有不少这类信息,你可以进去看看,希望能对你的复习有所帮助。
http://zhidao.baidu.com/question/46639294.html
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已知定义在R上的单调函数f(x),存在实数x0,使得对于任意实数x1、x2,总有f(x0x1+x0x2)=f(x0)+f(x1)+f(x2)恒成立。(1)求x0的值;(2)若f(x0)=1,且对于任意正整数n,有an=1/f(n),bn=f(1/2n)+1。记Sn=a1a2+a2a3+……anan+1,Tn=b1b2+b2b3+……bnbn+1。比较4Sn/3与Tn大小关系。
设f1(x)=2/(1+x),fn+1(x)=f1[fn(x)],an=[fn(0)-1]/[ fn(0)+2],(1)求数列{an}通项公式。(2)若Tn=a1+2a2+3a3+……2na2n,求数列{T2n}通项公式。
已知f(x)是定义在R上的不恒为0的函数,且对于任意a、b属于R都满足:f(ab)=af(b)+bf(a)。若f(2)=2,bn=f(2-n),求数列{bn}的前n项和。
已知B1(1,y1),B2(2,y2),•••,Bn(n,yn),•••,顺次为直线y=1/4x+1/12上的点,点A1(x1,0),A2(x2,0),•••,An(xn,0)顺次为x轴上的点,其中x1=a(0<a≤1)。对于任意n属于正整数,点An、Bn、An+1构成以Bn为顶点的等腰三角形。(1)求证:xn+2—xn为常数,并求出{xn}通项公式。(2)上述等腰三角形AnBnAn+1是否可能出现Rt三角形,如可能求出a的值,反之,说明理由。
已知f(x)=ax3+bx2+cx+d(a≠0)是定义在R上的函数,其图像交X轴于A、B、C三点,若B(2,0),f(x)在[-2,0]和[4,6]上是单调的,且在[-2,0]和[4,6]上有相同的单调性,在[0,2]和[4,6]上有相反的单调性。(1)求C的值。(2)求/AC/的取值范围。
四条直线l1:x+3y-15=0, l2:kx-y-6=0, l3:x+5y=0, l4:y=0 围成四边形。当k=( )时,此四边形有一个外接圆。
若a、b属于(0,π)求a、b的值使得cosa+cosb-cos(a+b)=3/2成立。
数列{an}满足a1=3/2,an+1=an2-an+1,则m=1/a1+1/a2+……+1/a2005的整数部分为()。
等差数列{an}中,an/a2n是一个与n无关的常数k,则k=()。
已知两个函数f(x)=7x2-28x-c, g(x)=2x3+4x2-40x.(1)若对于任意x属于[-3,3]都有f(x)≤g(x)成立,求实数c的取值范围。(2)若对于任意x1属于[-3,3],x2属于[-3,3],都有f(x1)≤g(x2)成立,求实数c的取值范围。
若函数y=f(x+1)的定义域为[-2,3],则f(2x-1)的定义域为()。
已知f(x)=2x+1,求f-1(2x+3)的反函数解析式。
设二次函数f(x)=ax2+bx+c(a>b>c)。已知f(1)=0,且存在实数m使得f(m)=-a。(1)推断f(x)在[0,+∞]上是否为单调函数,并说明理由。(2)设g(x)=f(x)+bx,对于x1、x2属于R且x1≠x2,若g(x1)=g(x2)=0,求/x1-x2/范围。(3)求证:f(m+3)>0
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