求一个C语言表白程序

能打动女孩的就行....要有新意哦..
2025-01-07 09:52:24
推荐回答(5个)
回答1:

#include

#include

#include

#define I 20

#define R 340

#include

int main()

{

char answer[10];

printf("遇到你\n我才发现\n曾经所有的条件\n似乎都成了我等你的借口\n\n");

printf("我对你的感情已经决堤\n所以\n请允许我,从今往后映入你\n明媚的眼\n");

printf("我\n想和你\n耳鬓厮磨,相濡以沫!");

printf("答应我吧!\n输入yes,你可以看到我的真心\n");

scanf("%s", answer);

float y, x, z, f;

for (y = 1.5f; y > -1.5f; y -= 0.1f)

{

for (x = -1.5f; x < 1.5f; x += 0.05f)

{

z = x * x + y * y - 1;

f = z * z*z - x * x*y*y*y;

putchar(f <= 0.0f ? "*********"[(int)(f*-8.0f)] : ' ');

}

putchar('\n');

}

long time;

for (;;)

{

system("color a");

for (time = 0; time<99999999; time++);

system("color b");

for (time = 0; time<99999999; time++);

system("color c");

for (time = 0; time<99999999; time++);

system("color d");

for (time = 0; time<99999999; time++);

system("color e");

for (time = 0; time<99999999; time++);

system("color f");

for (time = 0; time<99999999; time++);

system("color 0");

for (time = 0; time<99999999; time++);

system("color 1");

for (time = 0; time<99999999; time++);

system("color 2");

for (time = 0; time<99999999; time++);

system("color 3");

for (time = 0; time<99999999; time++);

system("color 4");

for (time = 0; time<99999999; time++);

system("color 5");

for (time = 0; time<99999999; time++);

system("color 6");

for (time = 0; time<99999999; time++);

system("color 7");

for (time = 0; time<99999999; time++);

system("color 8");

for (time = 0; time<99999999; time++);

system("color 9");

}

getchar();

return 0;

}

运行效果:


扩展资料:

printf函数使用注意事项

1、域宽

%d:按整型数据的实际长度输出。

如果想输出指定宽度可以指定域宽,%md--&gt;m域宽,打印出来以后,在控制台上,显示m位;

如果我们要打印的数的位数如果超过我们设定m则原样输出;

如果我们要打印的数的位数如果小于我们设定的位数,则补空白,具体如下:

如果m为正数,则左对齐(左侧补空白);

如果m为负数,则右对齐(右侧补空白)。

2、转义字符

如果想输出字符"%",则应该在“格式控制”字符串中用连续两个%表示。

如:printf("%f%%",1.0/3);输出结果:0.333333%。

回答2:

#include
#include
#include
// 获取控制台窗口句柄 微软官方网站的程序 直接拿来用了
HWND GetConsoleHwnd(void)
{
#define MY_BUFSIZE 1024 // Buffer size for console window titles.
HWND hwndFound; // This is what is returned to the caller.
char pszNewWindowTitle[MY_BUFSIZE]; // Contains fabricated
char pszOldWindowTitle[MY_BUFSIZE]; // Contains original

GetConsoleTitle(pszOldWindowTitle, MY_BUFSIZE);//获取控制台标题存入pszOldWindowTitle中
//设置控制台的标题为 时间数 进程ID
wsprintf(pszNewWindowTitle,"%d/%d",//把获取的数目,和当前进程ID输出到缓冲区pszNewwindowtitle中
GetTickCount(),//用于获取操作系统启动后的毫秒数
GetCurrentProcessId());//获取当前进程ID

SetConsoleTitle(pszNewWindowTitle);//更改控制台的标题为新内容

Sleep(40);

hwndFound=FindWindow(NULL, pszNewWindowTitle);//获取控制台的HWND号

SetConsoleTitle(pszOldWindowTitle);//更改控制台的标题为原始内容

return(hwndFound);//返回句柄
}


void drawXY()//绘制X和Y轴
{
HWND hWnd=GetConsoleHwnd();//获取控制台窗口句柄,用于设置画笔颜色
HDC hDC=GetDC(hWnd);
COORD dwSize;//记录窗体大小,用于设定坐标轴远点
HPEN hNewPen=CreatePen(PS_SOLID,1,RGB(255,0,0));//创建画笔对象
HPEN hOldPen=(HPEN)SelectObject(hDC,hNewPen);//选取画笔对象进行绘图
CONSOLE_SCREEN_BUFFER_INFO bInfo; // 窗口信息
HANDLE Hout=GetStdHandle(STD_OUTPUT_HANDLE);//获取控制台句柄
GetConsoleScreenBufferInfo(Hout, &bInfo );//获取控制台信息
dwSize=bInfo.dwMaximumWindowSize ;//获取窗口大小,此时获得的是字符模式下
//从字符到图像放大坐标轴8倍
dwSize.X *=8;
dwSize.Y*=8;
SetBkMode(hDC, TRANSPARENT);SetTextColor(hDC,255*255);
//绘制X轴各个特殊坐标
TextOut(hDC,dwSize.X-15,dwSize.Y/2-15,"X",1);
//Arc(hDC,100,100,300,300,350,500,350,500);//画圆 其中hDC表示画图句柄,100,100,300,300表示所使用的矩形区域,350,500表示画弧线的起点,350,500表明画弧线的终点 ; 
//绘制Y轴各个特殊坐标
TextOut(hDC,dwSize.X/2,0,"Y",1);
MoveToEx(hDC,0,dwSize.Y /2,NULL);
LineTo(hDC,dwSize.X,dwSize.Y/2);
MoveToEx(hDC,dwSize.X/2,0,NULL);
LineTo(hDC,dwSize.X/2,dwSize.Y);
ReleaseDC(hWnd,hDC); 
}
void draw(double p)
{
int i;
double x,y;
HWND hWnd=GetConsoleHwnd();//获取控制台窗口句柄,用于设置画笔颜色
HDC hDC=GetDC(hWnd);
COORD dwSize;//记录窗体大小,用于设定坐标轴远点
HPEN hNewPen=CreatePen(PS_SOLID,1,RGB(255,0,0));//创建画笔对象
HPEN hOldPen=(HPEN)SelectObject(hDC,hNewPen);//选取画笔对象进行绘图
CONSOLE_SCREEN_BUFFER_INFO bInfo; // 窗口信息
HANDLE Hout=GetStdHandle(STD_OUTPUT_HANDLE);//获取控制台句柄
GetConsoleScreenBufferInfo(Hout, &bInfo );//获取控制台信息
dwSize=bInfo.dwMaximumWindowSize ;//获取窗口大小,此时获得的是字符模式下
//从字符到图像放大坐标轴8倍
dwSize.X *=8;
dwSize.Y*=8;
//MoveToEx(hDC,0,dwSize.Y/2,NULL);
for(i=-180;i<=180;i++)
{
x=16*pow(sin(i*3.1415926/180),3.0)*p;
y=(13*cos(i*3.1415926/180)-5*cos(2*i*3.1415926/180)-2*cos(3*i*3.1415926/180)-cos(4*i*3.1415926/180))*p;


x=(x+16)*dwSize.X/32/2+dwSize.X/4;
y=-y/16*dwSize.Y/2.3+dwSize.Y/2;


x=x;
y=y;
MoveToEx(hDC,x,y,NULL);
LineTo(hDC,x+1,y+1);


}
}

void main()
{
double p;
drawXY();
for(p=0.6;p<=1;p=p+0.01)
draw(p);
system("PAUSE");
}

回答3:

#include 
#include 
#include 
#define I 20
#define R 340
int main()
{
int i,j,e;
int a;
long time;
system("title i love you");
for(i=1,a=I;i{
for(j=(int) ( I-sqrt(I*I-(a-i)*(a-i)) );j>0;j--)
printf(" ");
for(e=1;e<=2*sqrt(I*I-(a-i)*(a-i));e++)
printf("\3");
for(j=(int)
( 2*( I-sqrt(I*I-(a-i)*(a-i)) ) );j>0;j--)
printf(" ");
for(e=1;e<=2*sqrt(I*I-(a-i)*(a-i));e++)
printf("\3");
printf("\n"); }
for(i=1;i<80;i++)
{
if(i==25)
{
printf(" 我爱  女孩的名字   ");
i+=30;
}
printf("\3");
}
printf("\n");
for(i=1;i<=R/2;i++)
{
if(i%2||i%3)
continue;
for(j=(int) ( R-sqrt(R*R-i*i) );j>0;j--)
printf(" ");
for(e=1;e<=2*( sqrt(R*R-i*i) - (R-2*I) );e++)
printf("\3");
printf("\n");
}
 
for(; ; )
{
system("color a");
for(time=0;time<99999999;time++); system("color b");
for(time=0;time<99999999;time++); system("color c");
for(time=0;time<99999999;time++); system("color d");
for(time=0;time<99999999;time++); system("color e");
for(time=0;time<99999999;time++); system("color f");
for(time=0;time<99999999;time++);
system("color 0"); for(time=0;time<99999999;time++);
system("color 1"); for(time=0;time<99999999;time++);
system("color 2"); for(time=0;time<99999999;time++);
system("color 3"); for(time=0;time<99999999;time++);
system("color 4");
for(time=0;time<99999999;time++); system("color 5");
for(time=0;time<99999999;time++); system("color 6");
for(time=0;time<99999999;time++); system("color 7");
for(time=0;time<99999999;time++); system("color 8");
for(time=0;time<99999999;time++); system("color 9");
for(time=0;time<99999999;time++); system("color ab");
for(time=0;time<99999999;time++); system("color ac");
for(time=0;time<99999999;time++); system("color ad");
for(time=0;time<99999999;time++); system("color ae");
for(time=0;time<99999999;time++); system("color af");
for(time=0;time<99999999;time++); }
return 0;
}

来自c语言研究中心。

回答4:

main()
{int i,j;
for(i=0;i<9;i++)
{ if(i==0||i==8){ for(j=0;j<11;j++) printf("*");}
else {for(j=0;j<11;j++)
{if(j<7&&j>3) printf("*");
else printf(" ");}}
printf("\n");}
for(i=0;i<2;i++){
for(j=0;j<2-i;j++)printf(" ");
for(j=0;j<2*i+1;j++)printf("*");
for(j=0;j<5-2*i;j++)printf(" ");
for(j=0;j<2*i+1;j++)printf("*");
printf("\n");}
printf("***********\n");
for(i=0;i<6;i++)
{for(j=0;jfor(j=0;j<11-2*i;j++)printf("*");
printf("\n");}
for(i=0;i<5;i++)
{for(j=0;j<11;j++)
if(j<=1&&j>=0||j<=10&&j>=9) printf("*");
else printf(" ");printf("\n");}
for(i=0;i<5;i++)
{for(j=0;jprintf("**");
for(j=0;j<7-2*i;j++) printf(" ");
if(i==4) printf("*");
else printf("**\n");
}
}

离远一点 看看

回答5:

怎么运行不了


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