二次根下非负数∵x+1≥0∴x≥-1∵x-2≠0∴x≥-1且x≠2
(x+1)与x-2应该同号，得（x+1)(X-2)≥0所以解得x≤-1或x≥2且满足分式有意义故x≠2，综上，x≤-1或x＞2满意请采纳谢谢！同学请采纳我的啊楼上错了额===========
