1⼀(1*2)+1⼀(2*3)+1⼀(3*4)+1⼀(4*5)的简便计算的过程

2024-10-29 06:50:12
推荐回答(4个)
回答1:

原式=1-1/2+1/2-1/3……
即1/(n*(n+1))=1/n-1/(n+1)
所以原式=1-1/5=4/5.

回答2:

1/1*2+1/2*3+1/3*4+1/4*5
=(1-1/2)+(1/2-1/3)+(1/3-1/4)+(1/4-1/5)
=1-1/2+1/2+1/3-1/3+1/4-1/4-1/5
=1-1/5
=4/5

回答3:

1/1*2=1-1/2
1/2*3=1/2-1/3
1/3*4=1/3-1/4
1/4*5=1/4-1/5
原式=(1-1/2)+(1/2-1/3)+(1/3-1/4)+(1/4-1/5)
=1-1/2+1/2+1/3-1/3+1/4-1/4-1/5
=1-1/5
=4/5

回答4:

1-1/2+1/2-1/3+1/3-1/4+1/4-1/5=1-1/5=4/5