(1)先化简,再求值:5a2+3b2+2(a2-b2)-(5a2-3b2),其中a=?1 , b=12;(2)若A=x2-3x-6,B=2x2-4

2024-12-04 15:54:10
推荐回答(1个)
回答1:

(1)原式=5a2+3b2+2a2-2b2-5a2+3b2
=2a2+4b2
当a=-1,b=

1
2
时,原式=2+1=3;

(2)∵A=x2-3x-6,B=2x2-4x+6,
∴3A-2B=3(x2-3x-6)-2(2x2-4x+6)
=3x2-9x-18-4x2+8x-12
=-x2-x-30,
当x=-1时,原式=-1+1-30=-30.