设lim[(x+2a)⼀(x-a)]=8,则a=__.(x趋于0)

2024-11-14 07:19:10
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回答1:

应该是x趋于无穷大!否则极限为1!

(x+2a)/(x-a)=1+3a/(x-a)

lim[(x+2a)/(x-a)]^x=lim {[1+3a/(x-a)]^(x-a)/3a}^3ax/(x-a)
=e^3a=8
3a=3ln2

a=ln2!