在正方体ABCD-A1B1C1D1中,如图E、F分别是BB1,CD的中点,(1)求证:D1F⊥平面ADE;(2)cos?EF,CB1?(

2024-11-21 01:33:39
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回答1:

解:建立如图所示的直角坐标系,
(1)证明:不妨设正方体的棱长为1,
则D(0,0,0),A(1,0,0),D1(0,0,1),
E(1,1,

1
2
),F(0,
1
2
,0),
D1F
=(0,
1
2
,-1),
D A
=(1,0,0),
AE
=(0,1,
1
2
),
D1F
?
DA
=0,
D1F
?
AE
=0,