解:建立如图所示的直角坐标系,(1)证明:不妨设正方体的棱长为1,则D(0,0,0),A(1,0,0),D1(0,0,1),E(1,1, 1 2 ),F(0, 1 2 ,0),则 D1F =(0, 1 2 ,-1), D A =(1,0,0), AE =(0,1, 1 2 ),则 D1F ? DA =0, D1F ? AE =0,∴