a=根号3-根号2＞0b=2-根号3＞0c=根号5-2＞01/a=(根号3+根号2)/(3-2)=根号3+根号21/b=(2+根号3)/(4-3)=2+根号31/c=(根号5+2)/(5-4)=根号5+2∵2＞根号2∴2+根号3＞根号3+根号2∴1/b＞1/a∵根号5＞根号3∴根号5+2＞2+根号3∴1/c＞1/b∴1/c＞1/b＞1/a又a，b，c＞0∴a＞b＞c
